Besides, here the two-hybrid orbitals will contain a pair of electrons, and three hybrid orbitals will contain unpaired electrons, which again will overlap with the 2p orbital of F to form the resultant single bonds. All in all, during the hybridization, one 3s orbital, three 3p orbitals, and one of the 3d orbitals participate in the process that leads to the formation of five sp 3 d hybrid orbitals. Here, one of the paired electrons of Cl present in the 3p subshell remains as either a lone pair or unpaired. ![]() Now, when the Cl needs to combine with Fluorine atoms to form ClF 3, it requires three unpaired electrons to bond with the three F-atoms. If we closely notice the valence electronic configuration of Chlorine (Cl), it is represented as 3px 2, 3s 2, 3py 2, 3pz 1, 3d. ![]() This atom holds 7 valence electrons while ClF 3 should consist of 2 lone-pairs and 3 bond-pairs. If we speak about the hybridization of chlorine trifluoride, we should consider its central atom, which is Chlorine (Cl).
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